首页> 外文OA文献 >The structure of dichlorobisμ-(3-dimethylamino-1-propanethiolato)-μ-S,N-dipalladium(II), (I) Pd2(C5H12NS)2Cl2, and ac,bd,eg, fh-tetrakisμ-(3-piperidinemethanethiolato)-μ-S,N-tripalladium(II) dichloride dihydrate, (II) Pd3(C6H12NS)4Cl2.2H2O
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The structure of dichlorobisμ-(3-dimethylamino-1-propanethiolato)-μ-S,N-dipalladium(II), (I) Pd2(C5H12NS)2Cl2, and ac,bd,eg, fh-tetrakisμ-(3-piperidinemethanethiolato)-μ-S,N-tripalladium(II) dichloride dihydrate, (II) Pd3(C6H12NS)4Cl2.2H2O

机译:二氯双μ-(3-二甲基氨基-1-丙硫醇基)-μS,N-二钯(II),(I)Pd2(C5H12NS)2Cl2和ac,bd,例如fh-四环的结构μ-(3-哌啶甲硫醇根)-μS,N-三氯化二水合二钯(II)(II)Pd3(C6H12NS)4 Cl2.2H2O

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摘要

Mr=520.15, monoclinic, P21/n, a=7.207(2), B=20.616(4), c=5.854(1) A, β=96.05(1)º, V=864.9(6)A3, Z=2, Dx=2.00 Mg m-3, Mo Ka, = 0.71069 A, µ=2.553 mm-1, F(000)=512, 298 K, R=0.060 for 1492 reflections. (II): Mr=947.07, triclinic, Pl, a=12.666(7), b=10.595(6), c=6.572(5)A, a=98.30(2), = 97.04(2), = 99.84(2)º, V=850(2)A3, Z=1, Dx=1.85 Mg m-3, Mo Ka, =0.71069 A, µ=1.958 mm-1, F(000)=490, 298 K, R=0.071 for 1879 reflections. (I) was solved by direct methods, using MULTAN and DIRDIF, (II) by the heavy-atom method. The four-membered Pd, S, Pd, S rings have a syn-exo conformation, with dihedral angles between the S, Pd, S planes of 154.4(2) and 133.0(3)º for (I) and (II), respectively.
机译:Mr = 520.15,单斜晶,P21 / n,a = 7.207(2),B = 20.616(4),c = 5.854(1)A,β= 96.05(1)º,V = 864.9(6)A3,Z = 2,Dx = 2.00 Mg m-3,Mo Ka,= 0.71069 A,µ = 2.553 mm-1,F(000)= 512,298 K,R = 0.060(1492次反射)。 (II):Mr = 947.07,三斜晶,P1,a = 12.666(7),b = 10.595(6),c = 6.572(5)A,a = 98.30(2),= 97.04(2),= 99.84( 2)º,V = 850(2)A3,Z = 1,Dx = 1.85 Mg m-3,Mo Ka,= 0.71069 A,µ = 1.958 mm-1,F(000)= 490,298 K,R = 1879年反射的0.071。 (I)通过直接方法使用MULTAN和DIRDIF解决;(II)通过重原子方法解决。四元Pd,S,Pd,S环具有syn-exo构象,对于(I)和(II),S,Pd,S平面之间的二面角为154.4(2)和133.0(3)º,分别。

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    Solans Xavier;

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  • 年度 1983
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  • 正文语种 eng
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