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Synthesis and characterization of new alkoxide and aryloxide derivatives of titanium and zirconium. X-ray molecular structure of ZrCp2(OC6F5)2

机译:钛和锆的新醇盐和芳基氧化物衍生物的合成与表征。 ZrCp2(OC6F5)2的X射线分子结构

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摘要

Lithium or sodium alkoxides MOR (R double bond; length as m-dashCH2CHdouble bond; length as m-dashCMe2; M double bond; length as m-dash Li1; Na2; R double bond; length as m-dash C6F5; M double bond; length as m-dash Li3 were prepared by reaction of the alcohols with n-butyl lithium or sodium metal in hexane. Reaction of a hexane suspension of3 with SiClMe, afforded SiMe3(OC6F5)4, whereas the reaction of 3 equivalents of C6F5OH with AlMe3 in hexane led to Al(OC6F5)35. Compounds1 or2 react with one equivalent of [TiCp*Cl2Me] (Cp*double bond; length as m-dash C5Me5) in toluene to give [TiCp*ClMe(OCH2CHdouble bond; length as m-dashCMe2)]6. Complex6 reacts with AlEtCl2 to give quantitatively [TiCp*Cl3]. In the presence of water, the hydrolysis of6 takes palce giving the μ-oxo compound [{(TiCp*Cl)(μ − O)}3]. [TiCp*Cl2Me] reacted with an excess of the alcohol C6F5OH to give [TiCp*(OC6F5)3]7. [ZrCp2Cl2] reacted with two equivalents of pentaflurophenol in the presence of aniline to give the dialkoxide [ZrCp2(OC6F5)2]8. When the same reaction was carried out in a 1:1 molar ratio, a mixture of8 and the chloroalkoxide [ZrCp2Cl(OC6F5)]9 was obtained. A cleac reaction takes place when the μ-oxo compound [(ZrCp2Me)2(μ-O)] is treated with two equivalents of pentaflurophenol, leading to the isolation of the alkoxo complex [{ZrCp2(OC6F5)}2(μ-O)]10. The methylalkoxo derivative [ZrCp2Me(OC6F5)]11, was obtained by rection of [ZrCp2ClMe] with one equivalent of3. Alternative methods can be also be followed to synthesize8 and11. The crystal and molecular structure of8 has been determined by X-ray diffraction methods. The most interesting feature of this structure is the disposition of the (C6F5) ring planes, which are located practically on the reflection plane defined by O(1), Zr(1) and O(1)′.
机译:锂或钠的醇盐MOR(R双键;长度为m-dashCH2CH双键;长度为m-dashCMe2; M双键;长度为m-dash Li1; Na2; R双键;长度为m-dash C6F5; M双键;通过在正己烷中使醇与正丁基锂或钠金属反应制备长度为m-破折号Li 3;使3的己烷悬浮液与SiClMe反应,得到SiMe 3(OC 6 F 5)4,而使3当量的C 6 F 5 OH与HCl AlMe3在己烷中生成Al(OC6F5)35。化合物1或2与一当量甲苯中的[TiCp * Cl2Me](Cp *双键;长度为m-破折号C5Me5)反应,得到[TiCp * ClMe(OCH2CH双键;长度为m-dashCMe2)] 6。配合物6与AlEtCl2反应生成定量的[TiCp * Cl3]。在水的存在下,水解6得到淡黄色的化合物,生成μ-氧代化合物[{(TiCp * Cl)(μ-O)} 3]。[TiCp * Cl2Me]与过量的醇C6F5OH反应,得到[TiCp *(OC6F5)3] 7。[ZrCp2Cl2]与二当量的五氟苯酚在苯胺存在下反应,得到直径醇盐[ZrCp2(OC6F5)2] 8。当以1∶1的摩尔比进行相同的反应时,得到8和氯代烷氧化物[ZrCp2Cl(OC6F5)] 9的混合物。当用两当量的五氟酚处理μ-氧代化合物[(ZrCp2Me)2(μ-O)]时,发生裂解反应,从而导致分离出烷氧基复合物[{ZrCp2(OC6F5)} 2(μ-O) )] 10。甲基烷氧基衍生物[ZrCp2Me(OC6F5)] 11,是通过将[ZrCp2ClMe]与一当量的3反应而获得的。也可以遵循其他方法合成8和11。 8的晶体和分子结构已通过X射线衍射法确定。该结构最有趣的特征是(C6F5)环形平面的布置,它们实际上位于O(1),Zr(1)和O(1)'定义的反射平面上。

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