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Sample Sizes Based on Weibull Distribution and Normal Distribution for FRP Tensile Coupon Test

机译:基于Weibull分布和FRP拉伸优惠券测试的正态分布的样本尺寸

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摘要

Current guidelines stipulate a sample size of five for a tensile coupon test of fiber reinforced polymer (FRP) composites based on the assumption of a normal distribution and a sample coefficient of variation (COV) of 0.058. Increasing studies have validated that a Weibull distribution is more appropriate in characterizing the tensile properties of FRP. However, few efforts have been devoted to sample size evaluation based on a Weibull distribution. It is not clear if the Weibull distribution will result in a more conservative sample size value. In addition, the COV of FRP’s properties can vary from 5% to 15% in practice. In this study, the sample size based on a two-parameter Weibull distribution is compared with that based on a normal distribution. It is revealed that the Weibull distribution results in almost the same sample size as the normal distribution, which means that the sample size based on a normal distribution is applicable. For coupons with COVs varying from 0.05 to 0.20, the sample sizes range from less than 10 to more than 60. The use of only five coupons will lead to a prediction error of material property between 6.2% and 24.8% for COVs varying from 0.05 to 0.20.
机译:目前的准则规定了基于正常分布的假设和0.058的变异样品系数(COV)的纤维增强聚合物(FRP)复合材料的拉伸优惠券测试的样品尺寸。增加的研究已经验证了Weibull分布更适合于表征FRP的拉伸性质。然而,基于威布尔分布,很少有努力进行样本量评估。如果威布尔分布将导致更保守的样本大小值,则尚不清楚。此外,在实践中,FRP的特性的COV可以在5%到15%之间变化。在这项研究中,基于正态分布的基于双参数Weibull分布的样本大小进行比较。据透露,威布尔分布导致几乎与正常分布相同的样本大小,这意味着适用基于正态分布的样本大小。对于COVS不同于0.05至0.20的优惠券,样品尺寸范围不到10至60多次。只有五个优惠券的使用将导致材料性质的预测误差为6.2%和24.8%,因为COV从0.05到0.05 0.20。

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