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首页> 外文期刊>Russian Journal of Coordination Chemistry >Synthesis and Crystal Structures of (2.2.2-Cryptand)rubidium Chloride and Bromide Hydrates
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Synthesis and Crystal Structures of (2.2.2-Cryptand)rubidium Chloride and Bromide Hydrates

机译:(2.2.2-Cryptand)氯化rub和水合溴化物的合成及晶体结构

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摘要

Two complexes, (2.2.2-cryptand)mbidium chloride and bromide hydrates [Rb(Crypt-222]Hal · 3.5H2O (Hal = Cl (I) and Br (II)), are synthesized. The structures of isomorphic crystals of compounds I and II are studied by X-ray diffraction analysis. The crystals are trigonal: space group P3, Z=2;I: a = 11.810 A, c = 11.302 A; II: a = 11.890 A, c = 11.402 A. The structures are solved by a direct method and refined by the full-matrix least-squares method in the anisotropic approximation to R = 0.060 (I) and 0.077 (II) for 2650 (I) and 2700 (II) independent reflections (CAD-4 automated diffractometer, λMoK_α radiation). In crystals of complexes I and II, the [Rb(Crypt-222)]~+ cation of the host-guest type lies on the crystallographic axis 3 and has the approximate symmetry D3. In complexes I and II, the coordination polyhedron of the Rb~+ cation is a two-base-centered trigonal prism somewhat distorted to an antiprism. The crystals of compounds I and II contain H-bonded disordered cubes of the water molecules and Or or Br~- anions.
机译:合成了(2.2.2-cryptand)氯化bid和溴化物水合物[Rb(Crypt-222] Hal·3.5H2O(Hal = Cl(I)和Br(II)))的两种配合物,化合物的同构晶体结构通过X射线衍射分析研究I和II,晶体为三角形:空间群P3,Z = 2; I:a = 11.810A,c = 11.302A; II:a = 11.890A,c = 11.402A。对于2650(I)和2700(II)独立反射(CAD-4),采用直接方法求解结构,并通过全矩阵最小二乘法将各向异性近似为R = 0.060(I)和0.077(II)。自动衍射仪,λMoK_α辐射)在配合物I和II的晶体中,主体型客体的[Rb(Crypt-222)]〜+阳离子位于晶体学轴3上,并且具有对称性D3。 II,Rb〜+阳离子的配位多面体是一个以两个碱基为中心的三棱柱,在某种程度上扭曲成反棱镜,化合物I和II的晶体包含H键合的w的无序立方。分子和Or或Br-阴离子。

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