首页> 外文期刊>Neues Jahrbuch fur Mineralogie, Abhandlungen >The new mineral hermannroseite, CaCu(PO_4, AsO_4)(OH), the phosphate analogue of conichalcite, from Tsumeb, Namibia
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The new mineral hermannroseite, CaCu(PO_4, AsO_4)(OH), the phosphate analogue of conichalcite, from Tsumeb, Namibia

机译:来自纳米比亚tsumeb的新型矿物锰锌矿CaCu(PO_4,AsO_4)(OH),洋白石的磷酸盐类似物

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The new mineral hermannroseite (IMA-CNMNC No. 2010-006) has the chemical formula CaCu(PO_4, AsO_4)(OH). It is the phosphate analogue of conichalcite, CaCu(AsO_4)(OH) and belongs to the adelite group where it represents the fi rst phosphate end-member of this group. Hermannroseite is orthorhombic with space group P2_12_12_1. X-ray powder diffraction studies gave a: 7.328(7), b: 9.123(7), c: 5.769(6) A, V = 385.7(6) A~3 , Z = 4. The strongest refl ections in the X-ray powder diffraction data are as follows d_(obs). (A) (I, hkl): 2.808 (100, 130), 2.571 (73, 112), 3.092 (63, 201), 5.710 (56, 110) and 4.057 (37, 111). Hermannroseite was found in the Tsumeb mine, Tsumeb, Namibia. With a mean grain size of 0.7 μm hermannroseite occurs within botryoidal aggegates and crusts of micro crystalline conichalcite in association with hydroxylapatite, whitlockite, pseudomalachite and amorphous manganese oxides/hydroxides. Hermannroseite is translucent with a vitreous green colour. The calculated density is 4.08 g/cm~3, the calculated mean refractive index is 1.77. Chemical analyses gave (wt.%): CaO 22.80, CuO 34.52, ZnO 0.58, P_2O_5 15.16, As_2O_5 21.88, V_2O_5 1.02, H_2O_((by difference)) 4.04, sum 100.00 wt.%. The resulting empirical formula based on 5 anions is Ca_(0.96)(Cu_(1.03)Zn_(0.02))(P_(0.51)As_(0.45)V_(0.03))O_(3.94)(OH)_(1.06).
机译:新的矿物钙锰矿(IMA-CNMNC No. 2010-006)具有化学式CaCu(PO_4,AsO_4)(OH)。它是方石英CaCu(AsO_4)(OH)的磷酸酯类似物,属于人造石基团,代表该基团的第一个磷酸酯端基。钙锰矿是正交晶,空间群为P2_12_12_1。 X射线粉末衍射研究得出a:7.328(7),b:9.123(7),c:5.769(6)A,V = 385.7(6)A〜3,Z =4。X中最强的反射-射线粉末衍射数据如下d_(obs)。 (A)(I,hkl):2.808(100,130),2.571(73,112),3.092(63,201),5.710(56,110)和4.057(37,111)。在纳米比亚的楚梅布的楚梅布矿中发现了钙锰矿。在晶粒状团聚体和微晶方石英的壳中,与羟基磷灰石,水滑石,假孔雀石和无定形锰氧化物/氢氧化物结合,会产生平均粒径为0.7μm的钙锰矿。钙锰矿是透明的,具有玻璃绿色。计算出的密度为4.08g / cm〜3,计算出的平均折射率为1.77。化学分析得到(重量%):CaO 22.80,CuO 34.52,ZnO 0.58,P_2O_5 15.16,As_2O_5 21.88,V_2O_5 1.02,H_2O _((按差))4.04,总计100.00重量%。基于5个阴离子的经验公式为Ca_(0.96)(Cu_(1.03)Zn_(0.02))(P_(0.51)As_(0.45)V_(0.03))O_(3.94)(OH)_(1.06)。

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