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Oxygen-copper (II) interplay in the repair of semi-oxidized urate by quercetin bound to human serum albumin.

机译:氧铜(II)在槲皮素与人血清白蛋白结合的修复半氧化尿酸盐中相互作用。

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The 1:1 complex of copper (II) and human serum albumin (HSA) slowly reacts with radiolytically generated *O2- radical-anion at a rate constant of 6.1 x 10(6) M(-1) s(-1). Absorbance and fluorescence spectroscopies demonstrate that addition of an equimolar portion of quercetin (QH2) to the solution of the copper (II)-HSA complex induces a relocalization of the copper resulting in a ternary copper (II)-QH2-HSA complex. This form of quercetin slowly oxidizes in air-saturated solutions. A 10-fold excess urate, a plasma antioxidant, cannot displace copper (II) bound to HSA. In N2O-saturated solutions the ternary complex form of QH2 can repair the urate radical with a rate constant of 2.7 x 10(6) M(-1) s(-1) by an electron transfer reaction similar to that observed in the absence of copper (II). In O2-saturated solutions and in the absence of copper, HSA-bound QH2 fails to repair the urate radical because of the fast competitive reaction of *O2- with urate radicals. However, addition of equimolar copper (II)restores the electron transfer from QH2 to the urate radical. These contrasting results are tentatively explained either by an enhanced reactivity of copper (II) with *O2- in the ternary complex or by direct production of quercetin radicals via a copper-catalyzed reduction of the *O2- radicals by QH2.
机译:铜(II)和人血清白蛋白(HSA)的1:1络合物与放射产生的* O2-自由基阴离子缓慢反应,速率常数为6.1 x 10(6)M(-1)s(-1)。吸光度和荧光光谱表明,将等摩尔部分的槲皮素(QH2)添加到铜(II)-HSA络合物的溶液中会引起铜的重新定位,从而导致三元铜(II)-QH2-HSA络合物。槲皮素的这种形式在空气饱和的溶液中缓慢氧化。 10倍过量的尿酸盐(血浆抗氧化剂)不能取代与HSA结合的铜(II)。在N2O饱和溶液中,QH2的三元络合物形式可以通过电子转移反应修复尿酸根,其速率常数为2.7 x 10(6)M(-1)s(-1),类似于在不存在H2O的情况下观察到的反应。铜(II)。在O2饱和的溶液中并且在没有铜的情况下,HSA结合的QH2不能修复尿酸根自由基,因为* O2-与尿酸根自由基之间存在快速竞争性反应。但是,添加等摩尔的铜(II)可恢复电子从QH2到尿酸盐自由基的转移。这些相反的结果通过在三元络合物中铜(II)与* O2-的增强反应性或通过铜催化QH2还原* O2-自由基直接产生槲皮素自由基来解释。

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