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Synthetic methanol auxotrophy of Escherichia coli for methanol-dependent growth and production

机译:甲醇依赖生长和生产的大肠杆菌合成甲醇滋巢营养

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摘要

Methanol is a potentially attractive substrate for bioproduction of chemicals because of the abundance of natural gas and biogas-derived methane. To move towards utilizing methanol as a sole carbon source, here we engineer an Escherichia coli strain to couple methanol utilization with growth on five-carbon (C5) sugars. By deleting essential genes in the pentose phosphate pathway for pentose utilization and expressing heterologous enzymes from the ribulose-monophosphate (RuMP) pathway, we constructed a strain that cannot grow on xylose or ribose minimal media unless methanol is utilized, creating a phenotype termed "synthetic methanol auxotrophy". Our best strains were able to utilize methanol for growth at a rate of 0.17 +/- 0.006 (h(-1)) with methanol and xylose co-assimilation at a molar ratio of approximately 1: 1. Genome sequencing and reversion of mutations indicated that mutations on genes encoding for adenylate cyclase (cyaA) and the formaldehyde detoxification operon (frmRAB) were necessary for the growth phenotype. The methanol auxotrophic strain was further engineered to produce ethanol or 1-butanol to final titers of 4.6 g/L and 2.0 g/L, respectively. C-13 tracing showed that 43% and 71% of ethanol and 1-butanol produced had labeled carbon derived from methanol, respectively.
机译:由于天然气和沼气衍生甲烷的丰度,甲醇是一种用于化学品的潜在吸引力的基材。为了在利用甲醇作为唯一的碳源,我们在这里设计了大肠杆菌菌株,将甲醇利用与五碳(C5)糖的生长结合起来。通过剥去磷酸磷酸盐途径中的必需基因进行氢糖利用,并从核糖糖 - 单磷酸盐(臀部)途径表达异源酶,除非使用甲醇,否则在木糖或核糖最小培养基中构建了一种菌株,除非甲醇,产生称为“合成的表型”甲醇滋巢营养营养营养“。我们最好的菌株能够以0.17 +/- 0.006(H(-1))的速率利用甲醇和木糖共同化的甲醇,以摩尔比为约1:1。基因组测序和突变的逆转该突变对生长表型需要编码腺苷酸环化酶(CYAA)和甲醛排毒型(FRMRAB)的突变。进一步设计甲醇营养抑制菌株以分别生产乙醇或1-丁醇至4.6g / L和2.0g / L的最终滴度。 C-13追踪表明,43%和71%的乙醇和1-丁醇分别标记衍生自甲醇的碳。

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