首页> 外文期刊>Comptes Rendus Chimie >Tributyltin hydride-mediated free radical cyclization of allene-tethered oxime ethers,oxime esters and hydrazones.Influence of the substitutents borne by the C=N double bond on the course of the reaction
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Tributyltin hydride-mediated free radical cyclization of allene-tethered oxime ethers,oxime esters and hydrazones.Influence of the substitutents borne by the C=N double bond on the course of the reaction

机译:三丁基氢化锡介导的烯丙酸酯化肟醚,肟酯和的自由基环化。C= N双键所取代的取代基对反应过程的影响

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摘要

A set of allenic derivatives 1 bearing a C=N bond in #beta# position and diversely substituted in R~3 and Z was prepared.The behaviour of componds 1 towards the Bu_3Sn radical was tehn studied.Depending on the nature of R~3 and Z,products 2,3,and 4 were obtained in diverse ratios.When thesteric hindrance on the C-atom of the C=N bond was low(R~3=H),the product'normally'cbtained was 2.When the steric hindrance of R~3 was higher ,the formation of 3 and 4 became competitive.In this case,the ratio between 2,3,and 4 can be explainedon the basis of the polarit of R~3 and Z.The higher the electroattactive effect of R~3 and Z,the higher the quantity of2 and 4 in comparison with 3.
机译:制备了一组在#beta#位置带有C = N键并在R〜3和Z中不同取代的烯丙基衍生物1.研究了化合物1对Bu_3Sn自由基的行为。取决于R〜3的性质和Z分别得到2、3和4的产物。当C = N键的C原子上的空间位阻低(R〜3 = H)时,“正常”获得的产物为2。 R〜3的位阻越高,3和4的形成就越具有竞争性。在这种情况下,可以根据R〜3和Z的极化率来解释2,3,4之间的比率。 R〜3和Z的电活性效应,2和4的数量比3。

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