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Novel strategy for lipase-catalyzed synthesis of biodiesel using blended alcohol as an acyl acceptor

机译:使用混合醇作为酰基受体的脂肪酶催化生物柴油合成的新策略

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摘要

As a novel strategy, blended alcohols consisting of methanol and ethanol were used as acyl acceptors for biodiesel synthesis from soybean oil by lipase-catalyzed transesterification. Based on enzyme screening, Novozym 435 from Candida antarctica was selected for the reaction. The effects of the molar proportion of methanol in the blended alcohol, temperature, and enzyme loading were investigated for optimization of the reaction. In addition, the relative consumption rates of methanol and ethanol during the transesterification were studied. Among six proportions tested, 0 (100mol% ethanol), 20, 40, and 60mol% methanol in the blended alcohols exhibited high yields of biodiesel. For the optimum temperature, 30 °C was selected. The highest yield of biodiesel, over 95 wt%, was obtained at an enzyme loading of 5-10 wt% loading. In the lipase-catalyzed transesterification, the reactivity of methanol was significantly higher than that of ethanol.
机译:作为一种新的策略,由甲醇和乙醇组成的混合醇用作酰基受体,用于通过脂肪酶催化的酯交换反应从大豆油合成生物柴油。基于酶筛选,选择来自南极假丝酵母的Novozym 435进行反应。为了优化反应,研究了甲醇在混合醇中的摩尔比例,温度和酶载量的影响。另外,研究了酯交换反应中甲醇和乙醇的相对消耗率。在测试的六个比例中,混合醇中的0(100mol%乙醇),20、40和60mol%甲醇显示出高产率的生物柴油。为了获得最佳温度,选择了30°C。当酶负载量为5-10 wt%时,可获得超过95 wt%的最高生物柴油收率。在脂肪酶催化的酯交换反应中,甲醇的反应性明显高于乙醇。

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