首页> 外文期刊>Journal of Functional Analysis >On the largest Bell violation attainable by aquantum state
【24h】

On the largest Bell violation attainable by aquantum state

机译:关于量子态所能达到的最大的贝尔违规

获取原文
获取原文并翻译 | 示例
           

摘要

We study the projective tensor norm as a measure of the largest Bell violation of a quantum state. Inorder to do this, weconsider a truncated version of a well-known SDP relaxation for the quantum value of a two-prover one-round game, one which has extra restrictions on the dimension of the SDP solutions. Our main result provides a quite accurate upper bound for the distance between the classical value of a Bell inequality and the corresponding value of the relaxation. Along the way, wegive a simple proof that the best complementation constant of ?_2~n in ?_1(?_∞)is of order (In n)~(1/2)lnn. Asa direct consequence, weshow that we cannot remove a logarithmic factor when we are computing the largest Bell violation attainable by the maximally entangled state.
机译:我们研究了射影张量范数,作为对量子态最大的贝尔违反的度量。为了做到这一点,我们考虑了一个著名的SDP放宽的截断版本,该放宽的形式用于两个证明者的一轮游戏的量子值,该游戏对SDP解决方案的尺寸有额外的限制。我们的主要结果为Bell不等式的经典值和松弛的相应值之间的距离提供了一个非常准确的上限。在此过程中,简单地证明了在λ_1(λ_∞)中λ_2〜n的最佳互补常数是(In n)〜(1/2)lnn。作为直接的结果,我们表明,当我们计算最大纠缠态可达到的最大Bell违规时,我们无法去除对数因子。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号