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Mechanistic studies of the role of formaldehyde in the gas-phase methylation of phenol

机译:甲醛在苯酚气相甲基化中作用的机理研究

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The gas-phase reaction between phenol and formaldehyde was studied using Bronsted acidic and basic catalysts to gain insight into the components of phenol methylation with methanol.Formaldehyde and methylformate form from methanol during phenol methylation over basic catalysts.In the basic-catalyzed methylation of phenol with formaldehyde,the prevailing phenolic products were o-cresol and 2,6-xylenol;the same products were obtained in the methylation with methanol.When formaldehyde was used with the acidic catalyst,the distribution of products was similar to that obtained over basic catalysts.Comparing these results with those of methylation with methylformate,methyliodide,and methanol shows that with basic catalysts,formaldehyde was the true methylating agent in the reaction between phenol and methanol.This indicates that the transformation of methanol differentiates the reaction pattern in phenol methylation over basic or acidic catalysts.The role of the catalyst is to generate the methylating species;the nature of the latter then determines the type of products obtained in phenol methylation,whereas the catalyst type (either acidic or basic) has little influence on it.
机译:使用布朗斯台德酸性和碱性催化剂研究了苯酚和甲醛之间的气相反应,以了解甲醇中苯酚甲基化的组分。在碱性催化剂上苯酚甲基化期间,甲醇中的甲醛和甲基甲酸酯形成。与甲醛反应,主要的酚类产物为邻甲酚和2,6-二甲苯酚;在甲醇甲基化反应中得到的产物相同。当甲醛与酸性催化剂一起使用时,产物的分布与碱性催化剂相似将这些结果与用甲酸甲酯,甲基碘化物和甲醇进行甲基化的结果进行比较表明,在碱性催化剂下,甲醛是苯酚与甲醇反应中真正的甲基化剂。这表明甲醇的转化区分了苯酚甲基化反应的反应模式。碱性或酸性催化剂。催化剂的作用是产生乙基化物质;后者的性质决定了通过酚甲基化获得的产物的类型,而催化剂的类型(酸性或碱性)对其影响很小。

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