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首页> 外文期刊>Chemistry: A European journal >Iodine(III)-mediated preparations of nitrogen-containing sulfur derivatives:dramatic influence of the sulfur oxidation state
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Iodine(III)-mediated preparations of nitrogen-containing sulfur derivatives:dramatic influence of the sulfur oxidation state

机译:碘(III)介导的含氮硫衍生物的制备:硫氧化态的剧烈影响

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摘要

Reaction of sulfonamides with iodosobenzene leads to phenyliodinanes.A new catalysis reaction of the decomposition of these products in the presence of sulfoxides that allows the smooth synthesis of sulfoximines has been evidenced and studied;copper(II) salts were used to prepared compounds 4a-j and 5b,d,f,j,k from the corresponding,easily prepared,sulfoxides.The reactions proceed with retention of configuration at the sulfur center,and copper(II) triflate is the best candidate for the catalyst for the imination.Switching from sulfonamides to sulfinamides in the preparation of the starting iodinanes completely alters the reaction pathway:iodinanes are no longer accessible,and sulfonimidates 7a-j are obtained instead.This behavior can be rationalized by the increse in pK_a brought about by the removal of one oxygen atom from the sulfur center.Sulfonimidates are interesting molecules with varied applications.Optimization of their one-pot synthesis has been achieved by carrying out the reaction in acetonitrile.The stereochemical study has show that the transformation proceeds with global retention of the configuration at the sulfur center,albeit with erosion of the enantiomeric purity.A model accounting for this outcome is proposed.In addition,the presence of oxidized sulfonamide, by-products has been explained,and this latter pathway becomes the sole one when alchol is replaced by water.Good yields of the oxidized products are obtained.
机译:磺酰胺与碘代苯的反应生成苯基碘丁烷。已证明并研究了在亚砜存在下这些产物分解的新催化反应,该反应可以顺利合成亚砜肟;铜(II)盐用于制备化合物4a-j和5b,d,f,j,k分别来自相应的易于制备的亚砜。反应进行时会保留在硫中心的构型,三氟甲磺酸铜(II)是最理想的亚胺化催化剂。在起始碘的制备中,将磺酰胺转化为亚磺酰胺完全改变了反应途径:碘不再可用,而是获得了亚磺酰胺7a-j。这种行为可以通过去除一个氧原子导致pK_a的增加而合理化。磺酰胺盐是有趣的分子,具有广泛的应用。立体化学研究表明,尽管对映异构体纯度受到侵蚀,但转化过程仍在构型整体保留在硫中心的情况下进行。提出了解释这一结果的模型。此外,存在氧化的磺酰胺,已经解释了副产物,并且当水替代醇时,后一种途径成为唯一的途径。获得了高产率的氧化产物。

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