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首页> 外文期刊>Physics Letters, B. Nuclear Physics and High Energy Physics >Right-handed electrons in radiative muon decay
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Right-handed electrons in radiative muon decay

机译:辐射介子衰变中的右手电子

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摘要

Electrons emitted in the radiative decay mu(-) --> e(-)(v) over barv(mu)gamma have a significant probability of being right-handed, even in the limit m(e) --> 0. Such "wrong-helicity" electrons, arising from helicity-flip bremsstrahlung, contribute an amount alpha/4pi Gamma(0) to the muon decay width (Gamma(0) equivalent to G(F)(2)m(mu)(5)/(192pi(3))). We use the helicity-flip splitting function D-hf (z) of Falk and Sehgal [Phys. Lett. B 325 (1994) 509] to obtain the spectrum of the right-handed electrons and the photons that accompany them. For a minimum photon energy E-gamma = 10 MeV (20 MeV), approximately 4% (7%) of electrons in radiative mu-decay are right-handed. (C) 2003 Published by Elsevier B.V. [References: 13]
机译:在barv(mu)γ上以辐射衰减mu(-)-> e(-)(v)发射的电子即使在m(e)-> 0的极限内也有很大的惯性。由螺旋翻转致辐射产生的“错误螺旋性”电子对μ子衰减宽度(相当于G(F)(2)m(mu)(5)的贡献量为alpha / 4pi Gamma(0) /(192pi(3)))。我们使用Falk和Sehgal的螺旋翻转函数D-hf(z)[Phys。来吧B 325(1994)509]获得右手电子和伴随它们的光子的光谱。对于最小光子能量E-γ= 10 MeV(20 MeV),辐射mu衰变中约4%(7%)的电子为右手。 (C)2003年由Elsevier B.V.出版[参考文献:13]

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