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On Membership Comparable Sets

机译:关于成员资格可比集

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A set A is k(n) membership conparable if there is a polynomial-time computable function that, given k(n) instances of A of length at most n, excludes one of the 2~k(n) Possibilities for the memberships of the given strings in A. We show that if SAT is O(log n) membership comparable, then the NP-hard promise problem UniqueSAT can be solved in polynomial time. Our result settles an open question, suggested by Buhrman, Fortnow, and Torenvliet, and extends the work of Ogihara, Beigel, Kummer, Stephan, and Agrawal and Arvind. These authors showed that if SAT is c log n mem- bership comparable for c < 1, then NP = P, and that if SAT is O(log n) membership comparable, then UniqueSAT ∈ DTIME[ 2~(log~_n)]. Our proof also shows that if SAT is o(n) membership comparable, then UniqueSAT can be solved in deterministic time 2~(o(n)). Our main technical tool is an algorithm of Madhu Sudan (building on the work of Ar, Lipton, Rubinfeld, and Sudan) to reconstruct polynomials from noisy data through the use of bivariate poly- nomial factorization.
机译:如果存在一个多项式时间可计算函数,则给定A的k(n)个实例的长度最多为n个,则集合A是k(n)个隶属度的可乘函数,则排除了2个k(n)个隶属度的可能性我们证明,如果SAT是O(log n)隶属关系可比的,那么NP硬承诺问题UniqueSAT可以在多项式时间内求解。我们的结果解决了Buhrman,Fortnow和Torenvliet提出的一个开放性问题,并扩展了Ogihara,Beigel,Kummer,Stephan和Agrawal和Arvind的工作。这些作者表明,如果SAT的c log n成员可比性c <1,则NP = P,如果SAT的O(log n)成员资格可比,则UniqueSAT∈DTIME [2〜(log__n)]。 。我们的证明还表明,如果SAT是o(n)成员资格可比的,则UniqueSAT可以在确定时间2〜(o(n))内求解。我们的主要技术工具是Madhu Sudan(基于Ar,Lipton,Rubinfeld和Sudan的工作)的算法,该算法通过使用二元多项式因式分解从噪声数据中重建多项式。

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