首页> 外文期刊>Journal of the American Society of Brewing Chemists >The Effect of Ethanol-Sucrose Interactions on Specific Gravity. Part 2: A New Algorithm for Estimating Specific Gravity
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The Effect of Ethanol-Sucrose Interactions on Specific Gravity. Part 2: A New Algorithm for Estimating Specific Gravity

机译:乙醇-蔗糖相互作用对比重的影响。第2部分:一种新的比重估算算法

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One method for the estimation of specific gravity is the Tabarie equation: SGv = 1 + Σ(SGv_i - 1), which combines volume-adjusted binary solution specific gravities (SGv_i) independently. In a previous study, the Tabarie equation was found to be within the observed 95% confidence level for solute concentrations below 5% sucrose and 18% ethanol (by weight). However, when ethanol exceeds 7 mol% the deviation from observation is extreme. In this region, ternary solutions appear to expand because the mixing collapse of hydrogen-bonded bulk water is overestimated by the Tabarie model. In this paper, a new algorithm is proposed that assumes that change in solution volume during mixing is related only to change in water structure or the specific gravity of water in the presence of solutes. The model then takes the form of an ideal solution: SG = (Σw_i/SG_i)~(-1), where w_i is the mass fraction of species i. Ethanol-sucrose aqueous solutions were prepared by weight, mixed via sonication, and analyzed for density across the full range of sucrose solubility. Least squares regression analysis was used to fit the difference between the experimental specific gravity and theoretical ideal solution using polynomial cross-products of solute concentration (adjusted R~2 = 0.998; SE = 2.9 × 10~(-5); and n = 153).
机译:一种估计比重的方法是Tabarie方程:SGv = 1 +Σ(SGv_i-1),该方程独立地组合了体积调整后的二元溶液比重(SGv_i)。在先前的研究中,对于低于5%蔗糖和18%乙醇(按重量计)的溶质浓度,发现Tabarie方程在所观察到的95%置信度内。然而,当乙醇超过7mol%时,与观察值的偏差非常大。在该区域中,三价解似乎在扩大,因为Tabarie模型高估了氢键结合的散装水的混合塌陷。在本文中,提出了一种新算法,该算法假定在混合过程中溶液体积的变化仅与水的结构或溶质存在下水的比重有关。然后,模型采用理想解的形式:SG =(Σw_i/ SG_i)〜(-1),其中w_i是物种i的质量分数。按重量制备乙醇-蔗糖水溶液,通过超声混合,并在整个蔗糖溶解度范围内分析密度。使用最小二乘回归分析来拟合实验比重与理论理想溶液之间的差异,其中使用溶质浓度的多项式叉积(调整后的R〜2 = 0.998; SE = 2.9×10〜(-5); n = 153) )。

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