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Base station location and service assignments in W-CDMA networks

机译:W-CDMA网络中的基站位置和服务分配

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Designing a wideband code division multiple access (W-CDNIA) network is a complicated task requiring the selection of sites for radio towers, analysis of customer demand, and assurance of service quality in terms of signal-to-interference ratio requirements. This investigation presents a net-revenue maximization model that can help a network planner with the selection of tower sites and the calculation of service capacity. The integer programming model takes as input a set of candidate tower locations with corresponding costs, a number of customer locations with corresponding demand for traffic, and the revenue potential for each unit of capacity allocated to each demand point. Based on these data, the model can be used to determine the selection of radio towers and the service capacity of the resulting radio network. The basic model is a large integer program and requires a special algorithm for practical solution. Our algorithm uses a priority branching scheme, an optimization-gap tolerance between 1% and 10%, and two sets of global valid inequalities that tighten the upper bounds obtained from the linear prograrnming relaxation. The algorithm has been implemented in software for the AMPL/CPLEX system and an empirical investigation has been conducted. Using over 300 problem instances with up to 40 towers and 250 service locations, various combinations of algorithm settings have been evaluated. Using the recommended setting results in a design tool that generally runs in under 20 minutes on a 667 MHz AlphaStation.
机译:设计宽带码分多址(W-CDNIA)网络是一项复杂的任务,需要选择无线电塔的站点,分析客户需求并根据信噪比要求保证服务质量。这项调查提出了一个净收入最大化模型,该模型可以帮助网络规划人员选择塔楼站点和计算服务容量。整数规划模型将一组具有相应成本的候选塔位置,具有相应流量需求的多个客户位置以及分配给每个需求点的每个容量单位的潜在收入作为输入。基于这些数据,该模型可用于确定无线电塔的选择以及所得无线电网络的服务容量。基本模型是一个大型整数程序,需要特殊的算法来求解。我们的算法使用优先级分支方案,1%到10%的优化间隙公差以及两组全局有效不等式,这些不等式拉紧了从线性编程松弛获得的上限。该算法已在AMPL / CPLEX系统的软件中实现,并进行了实证研究。使用300多个带有40个塔和250个服务地点的问题实例,对算法设置的各种组合进行了评估。使用建议的设置将导致设计工具通常在667 MHz AlphaStation上运行不到20分钟。

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