设p是素数,k为自然数,d〉1为奇数。该文运用初等方法证明了不定方程xx+d)(z+2d)(x+3d)=P^2ky(y+d)(y+2d)(y+3d)没有正整数解。%That the Diophantine equation x(x + d) (x + 2d) (x + 3d) =P^2ky(y + d) (y + 2d) (y + 3d) has on positive integer solution is discussed in this paper, assuming that p is prime, k natural, and d odd, with d 〉 1, u- sing the elementary methods.
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