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Gene transfer through asymmetric somatic hybrids: Extent and predictability of donor chromosome elimination.

机译:通过不对称体细胞杂种进行基因转移:供体染色体消除的程度和可预测性。

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摘要

To produce highly asymmetric somatic hybrids, in order to transfer discrete traits between plant species, donor-chromosome elimination must be better understood. We examined the effects of radiation dose and time in culture on the elimination of donor genetic material. Mesophyll protoplasts of kanamycin-resistant donor Nicotiana plumbaginifolia were gamma-irradiated and fused with recipient mesophyll protoplasts of N. tabacum bearing the sulfur mutation (Su, phenotype yellow). Hybrid calli, selected on kanamycin-medium, were analyzed for N. plumbaginifolia genetic material by either dot-blot hybridization using a N. plumbaginifolia-specific repetitive DNA sequence probe, or by scoring the fraction of green hybrid calli (green = retained donor wild type allele). Both assays showed that the elimination of donor DNA increased with radiation dose, from 5 to 50 krad. At 50 krad, about one third of the hybrids lost 85% or more of the donor genome, which represents the retention of three, or fewer, donor chromosomes. In addition, donor DNA elimination continued for the first 12 months in culture.Alternatively, BrdU (0.1 to 10
机译:为了产生高度不对称的体细胞杂种,为了在植物物种之间转移离散的性状,必须更好地理解供体染色体的消除。我们检查了辐射剂量和培养时间对消除供体遗传物质的影响。用伽马射线照射耐卡那霉素的供体烟草Nicotiana plumbaginifolia的叶肉原生质体,并将其与带有硫突变(Su,表型为黄色)的烟草的受体叶肉原生质体融合。通过使用N. plumbaginifolia特异性重复DNA序列探针进行斑点印迹杂交或对绿色杂种愈伤组织进行分数计分(绿色=保留的供体野生输入等位基因)。两种测定均表明,供体DNA的消除随辐射剂量从5krad增加到50krad而增加。在50 krad时,大约三分之一的杂种会损失85%或更多的供体基因组,这表示保留了三个或更少的供体染色体。此外,在培养的前12个月中继续消除供体DNA。或者,BrdU(0.1至10

著录项

  • 作者

    Trick, Harold N.;

  • 作者单位

    The Florida State University.;

  • 授予单位 The Florida State University.;
  • 学科 Biology Molecular.Biology Genetics.
  • 学位 Ph.D.
  • 年度 1995
  • 页码 112 p.
  • 总页数 112
  • 原文格式 PDF
  • 正文语种 eng
  • 中图分类
  • 关键词

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