首页> 外文会议>International Symposium on Advances in Computational Heat Transfer >PRESSURE DROP AND HEAT TRANSFER IN SPIRALLY CORRUGATED TUBE FOR A COUNTER-FLOW HEAT EXCHANGER
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PRESSURE DROP AND HEAT TRANSFER IN SPIRALLY CORRUGATED TUBE FOR A COUNTER-FLOW HEAT EXCHANGER

机译:用于反流式热交换器的螺旋波纹管中的压降和传热

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This research studied heat transfer enhancement of a counter-flow heat exchanger by replacing a smooth inner tube with a spirally corrugated tube inside the heat exchanger. Results are obtained from the computational fluid dynamics (CFD) program. Performance of heat exchanger can be enhanced by increasing heat transfer area and increasing the turbulent intensity of fluid flow. A three-dimensional, steady, forced turbulent, and convectional flow model of fluid were developed in this research, water flowing inside smaller tube with an inner diameter of 20 mm, oil flowing in the annulus with the outer diameter of 76 mm., and domain length of 900 mm. The flow and physical parameters of the spirally corrugated tube; the corrugated pitch (p) and Reynolds number (Re) which affect friction factor (f) and Nusselt number (Nu) of the tube were studied in order to provide equations in which, later, was used to predict solutions numerically by calculating friction factor and Nusselt number of the tube. From the numerical results, we found that the friction factor depended on the corrugated pitch and Re as shown in the equation; f = -0.0091Re + 0.0715, and f = (3×10~(-5))p~3 -0.002p~2 -0.004 p~2 + 0.0043. However, the Nusselt number is expressed numerically as Nu = 89.93Re + 3.4578, and f = -1.5674p~3 -20.217p~2 -84.042 p~2 + 232.34. This simulation is valid for following ranges; 10000
机译:该研究通过在热交换器内用螺旋波纹管更换光滑的内管来研究逆流热交换器的热传递增强。结果是从计算流体动力学(CFD)程序获得的。通过增加传热面积并增加流体流动的湍流强度,可以提高热交换器的性能。在本研究中开发了一种三维,稳定,强制湍流和流体的对流流动模型,在较小的管内流动的内径为20mm,在环形线的外径为76mm的环。,和域长度为900毫米。螺旋波纹管的流动和物理参数;研究了影响管的摩擦系数(F)和露珠数(NU)的波纹间距(P)和雷诺数(RE),以提供后者通过计算摩擦因子来计算溶液的方程和管道的篮板。从数值结果来看,我们发现摩擦系数依赖于波纹间距和Re,如等式所示; f = -0.0091重+ 0.0715,f =(3×10〜(-5))p〜3 -0.002p〜2 -0.004 p〜2 + 0.0043。然而,NUSERET号码以nu = 89.93重+ 3.4578和f = -1.5674p〜3 -20.217p〜2 -84.042 p〜2 + 232.34。此模拟对于以下范围有效; 10000

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