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Design of shorter TE/sub 11/-to-HE/sub 11/ mode converters in a highly over-moded corrugated circular waveguide using a modified Chebyshev method

机译:使用改进的切比雪夫方法设计高度过模量的波纹圆形波导中较短的TE / sub 11 / to-HE / sub 11 /模式转换器

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A TE/sub 11/-to-HE/sub 11/ mode converter is realized by a section of corrugated waveguide which has a special profile of slot depths which vary from lambda /2 at the TE/sub 11/ end to lambda /4 at the HE/sub 11/. The design of the profile is considered in terms of an idealized model that considers the corrugated waveguide in terms of a continuous, but anisotropic, wall surface impedance having zero value in the phi direction and an average of the fin impedance and the slot input impedance in the z direction. A second assumption in the simplified design consideration is that there is coupling only between the TE/sub 11/ and TM/sub 11/ mode branches. This method has been used to design a converter with a conversion loss of 0.2 dB at a frequency of 60 GHz in a 1.094-in.-diameter waveguide. The length of the converter was calculated to be about 3.5 in. compared to about 4.1 in. for the constant coupling profile. The results of a scattering matrix computation indicates that the output of the converter is about 82.2% TE/sub 11/ mode (in terms of power) and 15.5% TM/sub 11/ mode. The phase difference between the TM/sub 11/ and TE/sub 11/ modes is about 18 degrees as calculated with the scattering matrix program, compared to the ideal case, where they should be in phase. This can be remedied by adding an about-1/2-in.-length section of smooth circular waveguide.
机译:TE / sub 11 / -to-HE / sub 11 /模式转换器是通过一段波纹波导实现的,该波导具有特殊的槽深度分布,从TE / sub 11 /端的λ/ 2到λ/ 4不等在HE / sub 11 /。根据理想化模型来考虑轮廓的设计,该模型以连续但各向异性的壁表面阻抗(在phi方向上具有零值)以及鳍状阻抗和缝隙输入阻抗的平均值来考虑波纹状波导。 z方向。简化设计考虑中的第二个假设是仅在TE / sub 11 /和TM / sub 11 /模式分支之间存在耦合。该方法已被用来设计一个转换器,该转换器在直径为1.094英寸的波导中在60 GHz的频率下的转换损耗为0.2 dB。计算得出,转换器的长度约为3.5英寸,而恒定耦合轮廓的长度约为4.1英寸。散射矩阵计算的结果表明,转换器的输出约为82.2%TE / sub 11 /模式(就功率而言)和15.5%TM / sub 11 /模式。用散射矩阵程序计算出的TM / sub 11 /和TE / sub 11 /模式之间的相位差约为18度,而理想情况下它们应该同相。这可以通过增加一个光滑的圆形波导的大约1/2英寸长的部分来解决。

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