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Why reaction rate does not always obey Arrhenius law during gas-solid reactions?

机译:为什么在气固反应中反应速率并不总是遵循阿伦尼乌斯定律?

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Gas-solid reactions are extensively studied by thermal analysis. To describe the kinetics of these reactions, the reaction rate da/dt (i.e. the derivative of the extent of conversion vs. time) is almost exclusively expressed by the product of a temperature function k(T) by a mathematical function f(alpha) depending on the kinetic model. In general, the temperature function k(T) is supposed to follow Arrhenius law with a pre-exponential term and the apparent activation energy E_(app) according to : k(T) = A exp(-E_(app)/RT) (1) Non-Arrhenius behavior has been observed in many cases such as for example CaO hydroxylation [1] and carbonation [2]. Simon [3] suggested that other k(T) functions than Arrhenius equation may be equally used. Moreover, the use of the Arrhenius equation in model-free methods when such equation is not relevant will necessarily induce E_(app) variation with the extent of conversion. Galwey [4] has recently stated that such variations are inconsistent with the Arrhenius activation model and he wonders how and why this variation. To precise the origin of such a complexity, it is necessary to come back to the mechanism of growth of the solid product phase which can be decomposed into a series of elementary steps: adsorption/desorption, external interface reaction, internal interface reaction, diffusion of species transferring from an interface to the other. Several reasons may be invoked to explain the non-Arrhenius behavior of k(T) function (in case of single reaction): 1 when the reaction conditions are far from equilibrium, and if a rate-determining step i governs the kinetics, the rate equation involves concentration terms which can be expressed by means of the equilibrium constants K_J (i and j are elementary steps of the growth mechanism, i ? j). Due to adsorption and/or desorption steps, it comes out that the rate may depend of temperature through terms deriving from Langmuir isotherm equation, and thus that it will not follow Arrhenius equation, 2 when the reaction conditions are near the equilibrium, the rate will never follow Arrhenius equation since the rate of the opposite reaction of the elementary rate-determining step cannot be neglected compared to that of the direct one. This is why we generally propose to write the rate equation using a function which accounts for possible complexity of the rate with thermodynamic variables [5]. Examples of rate equations where the temperature term is complex will be presented to illustrate these theoretical considerations.
机译:通过热分析对气固反应进行了广泛的研究。为了描述这些反应的动力学,反应速率da / dt(即转化程度与时间的导数)几乎完全由温度函数k(T)与数学函数f(alpha)的乘积表示。取决于动力学模型。一般而言,温度函数k(T)遵循Arrhenius律,并带有一个指数前项,并且视在活化能E_(app)根据:k(T)= A exp(-E_(app)/ RT) (1)在许多情况下都观察到非阿累尼乌斯行为,例如CaO羟基化[1]和碳酸化[2]。西蒙[3]建议,除阿伦尼乌斯方程外,其他k(T)函数也可以同样使用。而且,当无方程式方法不相关时在无模型方法中使用Arrhenius方程将必然引起E_(app)随转换程度的变化。 Galwey [4]最近指出,这种变化与Arrhenius激活模型不一致,他想知道这种变化如何以及为什么产生。为了精确说明这种复杂性的起因,有必要回到固体产物相的生长机理,该机理可以分解为一系列基本步骤:吸附/解吸,外部界面反应,内部界面反应,扩散物种从一个界面转移到另一个界面。可以使用以下几种原因来解释k(T)函数的非阿伦尼乌斯行为(在单个反应的情况下):1当反应条件远非平衡时,并且如果由速率决定的步骤i控制动力学,则速率为方程涉及浓度项,可以用平衡常数K_J表示(i和j是生长机理的基本步骤,i?j)。由于吸附和/或解吸步骤,结果表明速率可能取决于通过Langmuir等温方程得出的项的温度,因此当反应条件接近平衡时,它将不遵循Arrhenius方程2。绝对不要遵循Arrhenius方程,因为与直接反应速率相比,基本反应速率确定步骤的相反反应速率不能忽略。这就是为什么我们通常建议使用一个函数来编写速率方程,该函数考虑了具有热力学变量的速率的可能复杂性[5]。将给出温度项复杂的速率方程的示例,以说明这些理论考虑。

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