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What Makes a Knight?

机译:什么使骑士?

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摘要

Using the framework of assertoric semantics, we extended Smullyan's notion of a (classical) knight so that the notion is also defined for non classical languages like L in which we have the power to talk about all four possible answers of a knight, via the predicates 'T', 'F', 'B?' and 'N', and in which we may ask arbitrary self referential questions to the knight involving these predicates. We studied a notion of a knight with two non classical answers, 'neither' and 'both' and we used this conception to formulate a new Smullyan like riddle, which we called the four roads riddle, and we showed that it can be solved in 1 question by this paper's notion of a knight.
机译:使用断言语义的框架,我们扩展了Smullyan的(古典)骑士的概念,从而也为非古典语言(如L)定义了该概念,在该语言中,我们有权通过谓词讨论骑士的所有四个可能的答案。 'T','F','B?'和“ N”,其中我们可以向涉及这些谓词的骑士询问任意的自我参照问题。我们研究了一个具有两个非经典答案的骑士的概念,分别为“都不”和“两者”,并以此构想了一个新的Smullyan之类的谜语,我们将其称为四路谜语,并证明了它可以解决。本文提出的关于骑士的问题是一个问题。

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