首页> 外文会议>International Conference on Computer Science and Information Processing;CSIP 2012 >Cloning and sequence analysis of ribosomal protein L18 gene (rpl18) from Ailuropoda melanoleuca
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Cloning and sequence analysis of ribosomal protein L18 gene (rpl18) from Ailuropoda melanoleuca

机译:黑粉虱的核糖体蛋白L18基因(rpl18)的克隆与序列分析

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摘要

The rpl18 is a component of the 60s large ribosomal subunit playing an important role in ribosome. Based on the known nucleotide sequence of rpl18 genes, primers were designed to clone cDNA and genomic sequence of rpl18 gene from giant panda (Ailuropoda melanomleuca) successfully, and the structure characteristic of this gene was analyzed. The cDNA fragment of the rpl18 cloned from A. melanoleuca is 603bp in size, containing an open reading frame of 567bp. The deduced amino acid sequence has 188 residues, and the estimated molecular weight is 21.59 KD with 12.18 of PI. Alignment analysis implied that rpl18 shares high homology with the reported mammalian species, both at the level of DNA and protein. The predicted protein has 6 different patterns of functional sites. The data will not only enrich the information about rpl18 gene from giant panda genomic database.
机译:rpl18是60年代大核糖体亚基的组成部分,在核糖体中起重要作用。根据已知的rpl18基因核苷酸序列,设计了引物,成功克隆了大熊猫(Ailuropoda melanomleuca)的rpl18基因的cDNA和基因组序列,并对该基因的结构特征进行了分析。克隆自黑麦草的rpl18的cDNA片段大小为603bp,包含一个567bp的开放阅读框。推导的氨基酸序列具有188个残基,估计分子量为21.59 KD,PI为12.18。比对分析表明rpl18与报道的哺乳动物物种在DNA和蛋白质水平上具有高度同源性。预测的蛋白质具有6种不同的功能位点模式。这些数据不仅会丰富大熊猫基因组数据库中有关rpl18基因的信息。

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