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Annular bounds for the zeros of a polynomial from companion matrices

机译:环形边界的零多项式同伴矩阵

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Let p(z) = z(n) + a(n-1)z(n-1) + a(n-2)z(n-2) + ... + a(1)z + a(0) be a complex polynomial with a(0) not equal 0 and n >= 3. Several new upper bounds for the moduli of the zeros of p are developed. In particular, if alpha = root Sigma(n-1)(j=0) vertical bar a(j)vertical bar(2) and z is any zero of p, then we vertical bar z vertical bar(2) <= cos(2) pi/n+1 + vertical bar a(n-2)vertical bar + 1/4 (vertical bar a(n-1)vertical bar + alpha)(2) + 1/2 root alpha(2) - vertical bar a(n-1)vertical bar(2) + 1/2 alpha, which is sharper than the existing bound, given as, vertical bar z vertical bar(2) <= cos(2) pi/n+1 + 1/4 (vertical bar a(n-1)vertical bar + alpha)(2) + alpha, if and only if 2 vertical bar a(n-2)vertical bar < root Sigma(n-1)(j=0) vertical bar a(j)vertical bar(2) - root Sigma(n-2)(j=0) vertical bar a(j)vertical bar(2): The upper bounds obtained here enable us to describe smaller annuli in the complex plane containing all the zeros of p.
机译:... (0)不等于0 n > = 3。界限的模0 p发展。σ(n - 1) (j = 0)竖线(j)竖线(2)和z是任何零的p,那么我们竖线z竖线(2)< = cos(2)π/ n + 1 +竖线竖线(n - 2) + 1/4(竖线竖线(n - 1) +α)(2)+ 1/2根α(2)——竖线(n - 1)竖线(2)+1/2α,比现有的尖锐绑定,因为,竖线z竖线(2)< = cos(2)π/ n + 1 + 1/4(竖线竖线(n - 1) +α)(2)+α,如果和只有2竖线(n - 2)竖线<根σ(n - 1) (j = 0)竖线(j)竖线(2)——根σ(n - 2) (j = 0) (j)垂直的竖线杆(2):在这里使我们获得的上界在复平面来描述小轮包含所有的0 p。

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