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The solubility of an hydroxyaluminosilicate

机译:羟基铝硅酸盐的溶解度

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Hydroxyaluminosilicates (HAS) are critical secondary mineral phases in the biogeochemical cycle of aluminium. They are formed from the reaction of silicic acid (Si(OH)(4)) with an aluminium hydroxide template and act as a geochemical control of the biological availability of Al. There are two main forms of HAS which we have called HAS(A) and HAS(B) and which of these will predominate will depend upon the Si(OH)(4) to Al ratio in any one environment. In all but the most heavily weathered environments or those undergoing a progressive acidification Si(OH)(4) will be present in significant excess to Al and HASB will be the dominant secondary mineral phase. We have tried to determine the solubility of HAS(B(s)) so that its contribution to Al solubility control might be compared with other secondary minerals such as Al(OH)(3(gibbsite)). In preliminary experiments, the dissolution of HASB(s) was found to be non-congruent with almost no Al being released during 18 months ageing. We then demonstrated that HASB(s) was significantly less soluble than AI(OH)(3(s)) prepared under identical experimental conditions. We have used this information to describe a solubility expression for HAS(B(s)) at a predefined quasi-equibrium and to calculate a solubility constant.K*Al2Si2O5(OH)(4) = [Al2O4+][SiO2](2)[OH-](4)This unconventional solubility expression was derived to take account of the non-stoichiometric dissolution of HAS(B(S)) and included theoretical dissolution products which could then be substituted for the dissolution products which were measured experimentally.K*HAS(B) = [Al-r][Si(OH)(4)](2)[OH-](4)K*HAS(B) = 10(-40.6+/-0.15) (n = 17) (20 degreesC/I = 0.1 mol/L)The derivation of the solubility expression, though non-standard in approach, was validated by its application to Al(OH)(3(s)) and the calculation of a realistic solubility constant.K*Al2O(OH)(4) = [Al2O4+][OH-](4)K*Al(OH)(3(s)) = [Al-r][OH-](4) =10(-30.8+/-0.21) (n = 7) (20 degreesC/I = 0.1 mol/L)K*HASB(s) was found to be independent of [Si(OH)4] and predicted that HASB(s) could be the predominant secondary mineral phase controlling the solubility of Al in environments in which the pH 4.00 and [Si(OH)(4)] > 100 mumol/L. (C) 2004 Elsevier Ltd. All rights reserved.
机译:羟基硅铝酸盐(HAS)是铝的生物地球化学循环中的关键次生矿物相。它们是由硅酸(Si(OH)(4))与氢氧化铝模板的反应形成的,并充当Al生物有效性的地球化学控制。 HAS有两种主要形式,我们分别称为HAS(A)和HAS(B),其中哪一种占主导地位将取决于任何一种环境中的Si(OH)(4)与Al的比率。在除天气最恶劣的环境中或进行逐步酸化的所有环境中,Si(OH)(4)的含量将大大超过Al,而HASB将是主要的次生矿物相。我们试图确定HAS(B(s))的溶解度,以便可以将其对Al溶解度控制的贡献与其他次生矿物(如Al(OH)(3(三水铝石)))进行比较。在初步实验中,发现在18个月的老化过程中,HASB的溶解不完全,几乎没有Al释放出来。然后,我们证明了在相同的实验条件下制备的HASB(s)的溶解度明显低于AI(OH)(3(s))。我们已使用此信息来描述HAS(B(s))在预定义的准平衡下的溶解度表达式并计算溶解度常数。K* Al2Si2O5(OH)(4)= [Al2O4 +] [SiO2](2) [OH-](4)得出此非常规溶解度表达式是考虑到HAS(B(S))的非化学计量溶解,并且包括理论溶解产物,然后可以用实验测量的溶解产物替代K。 * HAS(B)= [Al-r] [Si(OH)(4)](2)[OH-](4)K * HAS(B)= 10(-40.6 +/- 0.15)(n = 17 )(20°C / I = 0.1 mol / L)溶解度表达式的推导方法虽然非标准,但已通过将其应用于Al(OH)(3(s))并计算了实际的溶解度常数进行了验证.K * Al2O(OH)(4)= [Al2O4 +] [OH-](4)K * Al(OH)(3(s))= [Al-r] [OH-](4)= 10(- 30.8 +/- 0.21)(n = 7)(20°C / I = 0.1 mol / L)K * HASB与[Si(OH)4]无关,并预测HASB可能为主要的次生矿物相控制Al在pH 4.00和[Si(OH)(4)]> 100 mumol / L的环境中的溶解度。 (C)2004 Elsevier Ltd.保留所有权利。

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