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首页> 外文期刊>Journal of Clinical Microbiology >Rapid spot test for the determination of esculin hydrolysis.
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Rapid spot test for the determination of esculin hydrolysis.

机译:快速斑点检测法测定七叶皂苷的水解。

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Esculin hydrolysis is a useful test in the differentiation of both gram-positive and gram-negative bacteria covering a wide spectrum of aerobes, facultative anaerobes, and anaerobes. Commonly utilized methods require a minimum of 18 h of incubation in broth or agar medium and utilize the production of a brown-black compound, due to the combination of ferric ions with the hydrolysis product esculetin, as indicator. A procedure is presented that requires 15 to 30 min for completion and utilizes fluorescence loss as the indicator of hydrolysis. Esculin fluoresces at 366 nm, whereas the hydrolysis product esculetin does not. Over 1,400 strains of gram-positive and gram-negative bacteria were tested. There was 98.4% of correlation between the spot test and esculin broth and 97% correlation with the bile-esculin agar.
机译:Esculin水解是区分多种需氧菌,兼性厌氧菌和厌氧菌的革兰氏阳性细菌和革兰氏阴性细菌的有用测试。常用的方法需要在肉汤或琼脂培养基中最少培养18 h,并且由于铁离子与水解产物七叶皂苷的结合而产生棕黑色化合物,这是指示剂。提出了需要15至30分钟才能完成并利用荧光损失作为水解指示剂的程序。 Esculin在366 nm发出荧光,而水解产物esculetin则不。测试了超过1400株革兰氏阳性和革兰氏阴性细菌。斑点试验和七叶树肉汤之间的相关性为98.4%,与胆汁-七叶树琼脂之间的相关性为97%。

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