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Compositions and the Alternate Fibonacci Numbers

机译:成分和备用斐波那契数

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摘要

For a given positive integer n, a composition of n is an ordered sum of positive integers that sum to n. For example, 1 + 1 + 1, 1 + 2, 2 + 1, and 3 are the four compositions of 3. If, however, we have two different kinds of ones - say 1 and 1', then we find that there are 13 compositions of 3. We'll show that for the positive integer n, when we have two different kinds of ones, there are F_(2n+1) compositions of n. [F_n denotes the n-th Fibonacci number, where F_0 = 0, F_1 = 1, and F_n = F_(n-1) + F_(n-2), for n ≥ 2.] Then we'll determine the number of times a positive integer k ( ≤ n) appears as a summand among these F_(2n+1) compositions of n. This will be followed by determining the numbers of plus signs and summands for these F_(2n+1) compositions of n, and then the numbers of odd and even summands. Next we'll find the numbers of rises, levels, and descents for the compositions and, finally, the number of palindromes among the compositions will be determined.
机译:对于给定的正整数n,n的组成是总和为n的正整数的有序和。例如,1 + 1 + 1,1 + 2,2 + 1和3是3的四个组成部分。但是,如果我们有两种不同的类型-比如1和1',那么我们发现有13的3的组合。我们将表明,对于正整数n,当我们有两种不同的整数时,存在n的F_(2n + 1)个组合。 [F_n表示第n个斐波那契数,其中F_0 = 0,F_1 = 1,并且F_n = F_(n-1)+ F_(n-2),对于n≥2。]然后,我们确定在这些n的F_(2n + 1)组合中,正整数k(≤n)的乘积出现。这之后将确定n的这些F_(2n + 1)组合的加号和加数的数量,然后是奇数和偶加数的数量。接下来,我们将找到组合物的上升,下降和下降的次数,最后,将确定组合物中回文的数目。

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